Integer In Words Conversion

The problem is given a number (upto a certain range) we need to convert the number in words.

Example:

1. 999 -> Nine Hundred Ninety-Nine
2. 4 -> Four
3. 0 -> Zero
4. -230 -> Minus Two Hundred Thirty.
5. 40 -> Forty

C Implementation

#include <stdio.h>

void print(int arr[], int n)
{
    int m, i;
    char *unit[] = {"","One","Two","Three","Four","Five","Six",
                    "Seven","Eight","Nine"};
    char *ten[] = {"","Ten","Twenty","Thirty","Forty",
                    "Fifty","Sixty","Seventy","Eighty","Ninety"};
    char *hundred[] = {"Ten","Eleven","Twelve","Thirteen","Fourteen",
                    "Fifteen","Sixteen","Seventeen","Eighteen","Nineteen"};
    
    for(i = 0; i < 5; i++) {
        if(i != 3) {
            if(arr[i]) {
                if((arr[i]%10) != 0) {
                    if(arr[i] < 10)
                        printf("%s ",unit[arr[i]]);
                    else if(arr[i] <= 19)
                        printf("%s ",hundred[arr[i]%10]);
                    else
                        printf("%s-%s ",ten[arr[i]/10],unit[arr[i]%10]);
                }
                else
                    printf("%s ",ten[arr[i]/10]);
                switch(i) {
                case 0: printf("Coror ");break;
                case 1: printf("Lakh ");break;
                case 2: printf("Thousand ");
                }
            }
        }
        else if(arr[3]) {
            printf("%s ",unit[(arr[i])]);
            printf("Hundred ");
        }
    }
    printf("\b.");
}

void divide(long int temp)
{
    int arr[10], i;
    long int div = 10000000;
    for(i = 0; i < 5; i++) {
        arr[i] = temp/div;
        temp = temp%div;
        if(i == 2) div /= 10;
        else div /= 100;
    }
    print(arr, 10);
}

int main(void)
{
    int i,j;
    long int num,temp;

    printf("Enter A Number(9-dig): ");
    scanf("%lld",&num);
    
    temp = (num < 0)? (-1 * num) : num;

    printf("In Words: ");
    if(num < 0) {
        printf("Minus ");
        divide(temp);
    }
    else if(num == 0) {
        printf("Zero.");
    }
    else {
        divide(temp);
    }
    return 0;
}

Enter A Number(9-dig): 3
In Words: Three.

Enter A Number(9-dig): 120
In Words: One Hundred Twenty.

Enter A Number(9-dig): 0
In Words: Zero.

Enter A Number(9-dig): -120
In Words: Minus One Hundred Twenty.

Enter A Number(9-dig): 99999
In Words: Ninety-Nine Thousand Nine Hundred Ninety-Nine.

Enter A Number(9-dig): 999999
In Words: Nine Lakh Ninety-Nine Thousand Nine Hundred Ninety-Nine.

Enter A Number(9-dig): 9999999
In Words: Ninety-Nine Lakh Ninety-Nine Thousand Nine Hundred Ninety-Nine.

Enter A Number(9-dig): 002
In Words: Two.